Tentukan bayangan garis 3x + 2y – 3 = 0 ditranslasikan oleh T = (1,2)

x' = x+ a
x = x' -a
x = x' -1

y' = y+b
y = y' -b
y = y' -2

subtitusikan ;
3x + 2y - 3 =0
3(x' -1) + 2(y'-2) -3 = 0
3x' -3 + 2y' -4 -3 = 0
3x' + 2y' - 10 = 0

jadi bayangannya 3x + 2y -10 = 0

3x + 2y - 3 = 0 T(1,2) —> 3(x+1) + 2(y+2) -3 = 0
= 3x + 3 + 2y + 4 - 3 = 0
= 3x + 2y + 4 = 0

NOTE :
Translasi (a,b) berarti variabel x+a dan variabel y+ b
A(x,y) T (a,b)—> A(x+a, y+b)

Maaf yaa kalau salah, semoga membantu ^_^