11 sampai 15 tolong besok dikumpulin
Matematika
Rochman2000
Pertanyaan
11 sampai 15 tolong besok dikumpulin
1 Jawaban
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1. Jawaban Anonyme
jawab
11.
D'hospital
limit (x -> 1) (4x +1)/.(6x +1) = (4 +1)/(6+1) = 5/7
12. limit = 1/3
13.
f'(x) < 0
x² - 2x - 3 < 0
(x - 3)(x + 1) <0
x < 3 atau x >1
14.
m = f'(x)
m = 6x - 4
untuk x = -1 , m = 6(-1) - 4 = -10
y -y1 = m (x -x1)
y - 3 = -10 (x +1)
y - 3 = -10x - 10
y = -10x - 7
10x + y + 7 = 0
15)
h(x) = 90 x - 3x²
maksimum jika h'(x)= 0
90 - 6x =0
-6x = -90
x= 15
h(15) = 90(15) - 3(15)²
h(15) = 675
laba = 675.000