1/2log(x^+2x)<-3 Bantu jawab please

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^(1/2)log (x² + 2x) < -3
x² + 2x > (1/2)^(-3)
x² + 2x > 2^3
x² + 2x - 8 > 0
(x + 4) (x - 2) > 0
x + 4 < 0
x < -4

x - 2 > 0
x > 2

Syarat :
x² + 2x > 0
x (x + 2) > 0
x > 0

x + 2 < 0
x < -2

Maka,
x < -4 atau x > 2