tolong bantu jawab soal no 23&25 serta cara penyelesaiannya yang super jelas ya

23.
y = u/v
y' = (u'v - uv')/(v²)

f'(x) = {(2x -3)(x² +2x +1) - (x² -3x)(2x +2) } /  (x² +2x +1)²
f' (2) = [ (4-3)(4+4+1) -(4-6)(4+2)} /(4+4+1)²
f'(2)= [ 1(9) + 2(6) ] / (9)²
f' (2)= (21)/(9)² = 7/27

25

y = sin³ (2x - 4)

u = 2x - 4
du/dx= 2

t = sin u
dt/du = cos u

y = t³
dy/dt = 3 t²

dy/dx = dy/dt. dt/du. du/dx
y' = 3 t². cos u . 2

y' = 3 sin² (2x-4) .cos (2x- 4) . 2
y' = 6 sin² (2x-4) cos (2x - 4)
jwb E