luas permukaan bola yg volume 36 cm³

[tex]V = \frac{4}{3} \pi r^{3} \\ 36 = \frac{r}{3} (4 \pi r^{2}) \\ 4 \pi r^{2} = 36 ( \frac{3}{r} ) \\ L = \frac{108}{r} [/tex]

Akan dicari nilai r
[tex]V = \frac{4}{3} \pi r^{3} \\ 36 = \frac{4}{3} \pi r^{3} \\ r^{3} = \frac{36x3}{4 \pi } \\ r^{3} = \frac{756}{88} \\ r^{3} = 8,6 \\ r = \sqrt[3]{8,6} \\ r = 2.05[/tex]

Maka
[tex]L = \frac{108}{r} = \frac{108}{2.05} = 52,7 cm^{2} [/tex]

Maaf yaa kalo jawabannya salah