Matematika

Pertanyaan

Akar-akar persamaan kuadrat x2 – 14x + 48 = 0 adalah x1dan x2. Jika nilai x2< x1, nilai 2x1 – x2 adalah …

2 Jawaban

  • x² - 14x + 48 = 0
    (x -8) (x-6)
    x = 8 x = 6
    x1 = 8, x2 = 6
    2x1 - x2 = 2(8) -6 = 16 -6 = 10


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  • x^2 - 14x + 48 = 0
    (x - 6)(x - 8) = 0
    x - 6 = 0 atau x - 8 = 0
    x = 6 atau x = 8

    x2 < x1
    x1 = 8
    x2 = 6

    2x1 - x2
    = 2(8) - 6
    = 16 - 6
    = 10

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