Mohon bantuanya | 2x - 3 | > | x - 4 |

| 2x-3 | > | x-4 |
=(2x-3)^2 > (x-4)^2
=4x^2-12x+9 > x^2 -8x +16
=4x^2-x^2 -12x+8x+9-16 >0
=3x^2-4x-7 > 0
=(3x-7)(x+3) > 0

3x-7 = 0
3x = 7
x = 7/3

x+3 = 0
x = -3

Hp {x l x< -3 atau x > 7/3}

| 2x - 3 | > | x - 4 |
(2x - 3)² > (x - 4)²
4x² - 12x + 9 > x² - 8x + 16
3x² - 4x - 7 > 0
(3x - 7)(x + 1) > 0
x < -1   atau   x > 7/3

HP = {x| x < -1   atau   x > 7/3}