Matematika

Pertanyaan

2log 18 - 2 log 8 akar 2 + 2 log 1/27 - 2 log 1/3

2 Jawaban

  • jawab
    (²log 18 - ²log 8√2 + ²log 1/27 - ²log 1/3 =

    = ²log  ( 18 : 8√2 x 1/27 : 1/3)
    = ²log  ( 18√2 /16 x  1/ 27  x  3)
    = ²log  (18√2  /16  x 1/9)
    = ²log  (2√2)/(16) 
    = ²log 2^(5/2). 2^(-4)
    = ²log 2^(-3/2)
    = - 3/2 
  • penyelesaian
    ²log 18 - ²log 8√2 + ²log 1/27 - ²log 1/3
    = ²log (18 ÷ 8√2 x 1/27 ÷ 1/3)
    = ²log (18 x 1/16 √2 x 1/27 x 3)
    = ²log (18/144 √2)
    = ²log (1/8 √2)
    = ²log (2⁻³ x √2)
    = -5/2 ²log 2
    = -5/2

    #semogamembantu

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