Jika log 2 = 0,3010 dan log 3 = 0,4771,maka log 12 adalah

[tex] log_{}(12) \\ = log_{}(4) + log(3) \\ = log(2) + log(2) + log_{}(3) \\ = 0.3010 + 0.3010 + 0.4771 \\ = 1.0791[/tex]