Diketahui f(X) =ax+b f(2)=8 danf(4)=14,tentukan nilaif f(0)_f(3)

f(x) = ax + b

f(2) = 2a + b = 8
f(4) = 4a + b = 14
         ------------------ (-)
            2a = 6
              a = 3

2a + b = 8
2(3) + b = 8
b = 8 - 6
b = 2

jadi 
f(x) = 3x + 2

f(0) - f(3)
= 3(0) + 2 - 3(2) + 2
= 0 + 2 - 6 + 2
= -6

f (x)=ax+b
f (4)=4a+b=14
f (2)=2a+b=8
jdikan pers linear didpt a=3, b=2.
f (x)=3x+2
f (0)-f (3)
=0+2-3 (3)+2
=2-7
=-5