Hasil dari (3x+1)√3x²+2x-4) dx

Materi : Integral tak tentu
Kelas : XI semseter 2 atau XII semester 1

Int ((3x+1)√3x^2+2x-4) dx
= int ((3x+1) (3x^2+2x-4)^1/2) dx
= → Gunakan rumus subsitusi, yaitu
= (3x+1) (3x^2+2x-4)^1/2+1
= (3x+1)/6x+2(3/2) (3x^2+2x-4)^3/2
= 1/2(3/2) (3x^2+2x-4)^3/2
= 1/3 (3x^2+2x-4)^3/2
= 1/3 (3x^2+2x-4)^3/2
= 1/3 (3x^2+2x-4)√3x^2+2x-4) + c

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