tolong dong jawab pakai cara no 3 dan 4 plissss

^grafik untk no 3

3. Q1 = m•c•ΔT
= 400gr x 0,5 kal/gr^C x (-4^C - 0^C)
= 400gr x 0,5 kal/gr^C x 4^C = 800 kal
Q2 = 400 gr x 80 kal/gr
= 32000 kal
Q3 = m•c•ΔT
= 400gr x 1 kal/gr^C x (80^C - 0^C)
= 400gr x 1 kal/gr^C x 80^C
= 32000 kal
Qtotal = Q1 + Q2 + Q3
= 800 kal + 32000 kal + 32000 kal = 64.800 kal

2. Dik: m = 6 kg
To = 30^C
T = 90^C
ΔT = 90^C - 30^C = 60^C
C = 460 J/Kg^C
Dit: Q = ...?
Q = m•c•ΔT
= 6kg x 460 J/Kg^C x 60^C
= 165.600 J

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