persamaan garis lurus yang melalui (3,-6) dan sejajar garis 5x-4y=7 adalah a.4x+5y=-18 b.4x+5y=28 c.5x-4y=-9 d.5x-4y=39

5x-4y=7 (3,-6) x1=3 y1=-6
m=-a/b
=-5/-4
=5/4
=y-y1=m(x-x1)
=y-(-6)=5/4(x-3)
=y+6=5/4 x-3
=4 (y+6)=5 (x-3)
=4y+24=5x-15
=4y-5x=-24-15
=4y-5x=-39
=5x-4y=39
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