tentukan persamaan garis lurus yang melalui titik (3,1) dan (-2,2)!

persamaan garis
y-y1/y2-y1=x-x1/x2-x1
y-1/2-1=x-3/-2-3
y-1/1 = x-3/-5
-5(y-1)= 1(x-3)
-5y+5= x-3
-5y = x-3-5
-5y = x-8
x+5y-8 =0. (1)
x+5y = 8. (2)
y = x/-5+8/5