rumus suatu fungsi dinyatakan dengan f(x)=3+ax.Jika f(a+1)=a²-2 nilai a

[tex]f(a + 1) = 3 + ax \\ { {a}^{2} } - 2 = 3 + a(a + 1) \\ {a}^{2} - 2 = 3 + {a}^{2} + a \\ a + 3 = - 2 \\ a = - 5[/tex]