gradien garis yang melalui titk (-3,8) dan (5,-3) adalah? Pake caranya tolong

[tex] \frac{y - y1}{y2 - y1 } = \frac{x - x1}{x2 -x1} \\ \frac{y - 8}{ - 3 - 8} = \frac{x + 3}{5 + 3} \\ \frac{y - 8}{ - 11} = \frac{x + 3}{8} \\ 8y - 64 = - 11x - 33 \\ 8y + 11x = - 33 + 64 \\ 8y + 11x = 31[/tex]
Maaf kalo salah hitung :)
Gradien = -11/8
Rumusnya =-a/b
a=x
b=y

Diket :
x1 = -3
x2 = 5
y1 = 8
y2 = -3

Jawab :
m = y2-y1/x2-x1
m = -3-8/5-(-3)
m = -11/8

Maaf jika ada kesalahan :)