Carilah titik puncak dan sumbu simetri dan fungsi kuadrat y=4x-x² Tolong caranya

f (x) = 4x - x^2
f (x) = x^2 + 4x
sumbu simetri x = - -4/2(-1)
x = 4/-2 = -2
f (-2) = -(-2)^2 -4(-2)
= -4 + 8
= 4
Puncak ( -2, 4 )