sistem persamaan {2x+3y=11{5x+3y=23,maka nilai x+y=

Eliminasi y
2x + 3y = 11
5x + 3y = 23
__________ _
−3x = −12
x = −12/−3
x = 4

Substitusi x = 4 ke pers. 1
2x + 3y = 11
2(4) + 3y = 11
8 + 3y = 11
3y = 11 − 8
3y = 3
y = 3/3
y = 1

x + y = 4 + 1
= 5

Metode Eliminasi
2x + 3y = 11
5x + 3y = 23
___________ -
-3x. = -12
x. = -12/-3
x. =4

Metode Substitusi
2x + 3y = 11
2.4 + 3y = 11
8 + 3y = 11
3y = 11-8
3y = 3
y = 3/3
y = 1

nilai x + y adalah 4 + 1 = 5

semoga membantu yaa:)