Persamaan 10^2logx2-7(10^2log x) + 10 = 5
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Persamaan 10^2logx2-7(10^2log x) + 10 = 5
1 Jawaban
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1. Jawaban syifajs
[tex]10 {}^{2} log(x {}^{2} ) - 7(10 {}^{2} logx) + 10 = 5 \\ 10.2{}^{2} log(x ) - 7 \times 10 {}^{2} log(x) + 10 = 5 \\ 20 {}^{2} log(x) - 70 {}^{2} log(x) + 10 = 5 \\ - 50 {}^{2} log(x) + 10 = 5 \\ - 50 {}^{2} log(x) = 5 - 10 \\ - 50 {}^{2} log(x) = - 5 \\ \\ bagi \: kedua \: ruas \: dgn \: - 50 \\ sehingga \\ {}^{2} log(x) = \frac{1}{10} \\ x = 2 ^{ \frac{1}{10} } \\ x = \sqrt[10]{2} [/tex]