fraksi mol urea dalam larutn yg dibuat dgn melarutkn 30 gr urea (Mr=60) ke dlm 0,09kg air(Mr=18) ? A ½ B 1/10 C 1/11 D 1/5 E 5
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Pertanyaan
fraksi mol urea dalam larutn yg dibuat dgn melarutkn 30 gr urea (Mr=60) ke dlm 0,09kg air(Mr=18) ?
A ½
B 1/10
C 1/11
D 1/5
E 5
A ½
B 1/10
C 1/11
D 1/5
E 5
2 Jawaban
-
1. Jawaban argbobyp0nlw9
mol = massa/Mr
mol urea = 30/60 = 1/2 mol
mol air = 90/18 = 5
Xt = nt / nt + np
= (1/2) / (1/2) + 5 = (1/2) / 11/2 =1/11 -
2. Jawaban pedopedopedo
Mol urea = gr/Mr = 30/60
= 0.5
Mol air = gr/Mr = (0.09×1000)/18
= 5
Fraksi mol = mol urea/mol campuran
= 0.5/0.5+5
= 0.090 = 1/11 ( C )