hasil dari integral (x-3).(x2 -6X+1)~3 dx =

∫(x - 3) (x² - 6x + 1)³  dx

misalkan
u = x² - 6x + 1
du = 2x - 6 dx
du = 2(x - 3) dx
du/2 = (x - 3) dx
maka bentuk integral menjdai
∫(x - 3) (x² - 6x + 1)³  dx
= 1/2 ∫ u³ du
= 1/2 [u⁴/4] + C
= (1/8) u⁴ + C
= (1/8) (x² - 6x + 1)⁴ + C