log 120 - log 30 + log 45 +log 1/180 adalah

[tex] {}^{10} log(120) - {}^{10} log(30) + {}^{10} log(45) \\ = {}^{10} log( \frac{120 \times 45}{30} ) \\ = {}^{10} log(4 \times 45) \\ = {}^{10} log(180) \\ = {}^{10} log(10 \times 18) \\ = {}^{10} log(10) + {}^{10} log(18) \\ = 1 + {}^{10} log(18) \\ \\ log(120) - log(30) + log(45) + log( \frac{1}{180} ) \\ = 1 + {}^{10} log(18) + {}^{10} log( \frac{1}{180} ) \\ = 1 + {}^{10} log( \frac{1}{10} ) \\ = 1 + {}^{10} log(10 {}^{ - 1} ) \\ = 1 - 1 \\ = 0[/tex]