nilai 5log20 - 5 log6 + 5log 18 - 5log12 adlah

5log20-5log6+5log18-5log12
= 5log20x18/6x12
= 5log360/72
= 5log5
= 1

Maaf jika ada kesalahan :)

[tex] {}^{5} log(20) - {}^{5} log(6) + {}^{5} log(18) - {}^{5} log(12) \\ = ({}^{5} log( \frac{20 \times 18}{6} ) ) - {}^{5} log(12) \\ =( {}^{5} log(20 \times 3) ) - {}^{5} log(12) \\ = {}^{5} log(60) - {}^{5} log(12) \\ = {}^{5} log(5) \\ = 1[/tex]