Jika a =0,333 . . . dan b=√90-√90-√90- . . . maka nilai a log b = . . .

LogAritMa

a = 0,333...
a = 1/3 = 3^-1

b = √(90 - √(90 - √...
b² = 90 - b
b² + b - 90 = 0
(b + 10)(b - 9) = 0
b = 9 = 3^2

a'log b
= (3^-1)'log 3^2
= 2/(-1) . 3'log 3
= -2