Simpangan baku dari 1,2,4,5,8 adalah...

jawab
xi = 1,2,4,5,8
n = 5
Σxi = 1+2+4+5+8  = 20
X = 20/5 = 4

s² =(1-4)² + (2-4)²+(4-4)²+(5-4)²+(8-4)²
s² = 9 + 4+0+ 1+ 16
s² =30

simpangan baku = s = √(s²/n) =√(30/5) =√6