²log 24 + ³log 12 - ² log 3 + ³log 1/4

²log 24 + ³log 12 - ²log 3 + ³log 1/4
= ²log2×12 + ³log3×4 - ²log 3 + ³log 1/4
= 1 + ²log12 + 1 + ³log4 - ²log 3 + ³log 1/4
= 2 + ²log12 - ²log 3 + ³log4 + ³log 1/4
= 2 + ²log12/3 + ³log4×1/4
= 2 + ²log4 + ³log1
= 2 + ²log(2²) + 0
= 2 + 2 + 0
= 4

Maaf kalau salah. Semoga membantu ^^

2log 24 +3log12-2log 3+3log 1/4 =???

maka 2log24-2log3+3log12 +3log1/4
INGAT!! berlaku hukum :
alogb+alogc = bxc
blogc-blogd = c/d
jadi..
2log24+2log3 = 8
3log12+3log1/4 = 12x1/4 = 3
jadi 8+3 = 11
semoga membantu kamu ya dek.. semangat terus belajar mtknya :)))