segitiga abc dan segitiga def kongruen,bedar sudut def

jawabannya C.86
karna
180°-(58°+36°)
=180°-94°
=86°

sudut Abc=Edf
sudut A=E
sdt B=D=36
sdt C=F=58

ACB = EFD = 58'
CBA = EDF = 36'
CAB = DEF = 86' +
                       180'