diketahui sistem persamaan linear 5x-4y=-1 dan 10×+2y=3

[tex]5x - 4y = - 1 \\ 10x + 2y = 3 \\ samakan \: nilai \: koefisien\: y \: atas \: kali \: 1\: bawah \: kali \: 2 \\ 5x - 4y = - 1 \\ 20x + 4y = 6 \\ ditambah \\ 25x = 5 \\ x = \frac{1}{5} \\ subskan \: x \\ 5x - 4y = - 1 \\ 5( \frac{1}{5} ) - 4y = - 1 \\ 1 - 4y = - 1 \\ - 4y = - 2 \\ y = \frac{1}{2} [/tex]
semoga bermanfaat

5x-4y=-1(kali2)
10x+2y=3(kali1)

10x-8y=-2
10x+2y=3
—————— -
-10y=-5
y=-5/-10
y=5/10

5x-4(5/10)=-1
5x-2=-1
5x=-1+2
5x=1
x=1/5