3log(x-2)+3log(x-4)=1 Pake cara yaa

LogAritMa

³log (x - 2) + ³log (x - 4) = 1
³log (x - 2)(x - 4) = ³log 3
(x - 2)(x - 4) = 3
x² - 6x + 8 - 3 = 0
(x - 1)(x - 5) = 0
x = 1 atau x = 5

Nilai x yg memenuhi :
1 dan 5

Syarat :
X > 2
X > 4

³log(x-2) + ³log (x-4) = ³log3
(x-2) (x-4) = 3
x² -6x + 8 - 3 = 0
x² - 6x + 5
(x-5) (x-1)
X = 5 atau X = 1

Jadi yang memenuhi hanya X = 5