Kimia

Pertanyaan

kk bisa di bantu ngga
kk bisa di bantu ngga

1 Jawaban

  • Orde A
    {[A]2 / [A]1}^x = V2/V1
    {0,2 / 0,1} ^ x = 16/ 4
    2^x = 4
    2^x = 2^2
    X = 2

    Orde B
    {[B]3 / [B]1}^y = V3/V1
    {0,3/ 0,1} ^ y = 12/ 4
    3^y = 3
    3^y = 3^1
    y = 1

    Orde reaksi total
    x + y = 2 + 1 = 3

    Persamaan laju reaksi
    V = k [A]^x [B]^y
    V = k [A]^2 [B]

    Harga k
    Menggunakan data ke 1
    k = V1 / [A]^2 [B]
    = 4 / (0,1)^2 (0,1)
    = 4 / 1× 10^-3
    = 4 × 10^3
    = 4000


    Laju reaksi [ A ] = 0.1 [ B] = 0.2
    V = k [A]^2 [B]
    = 4000 × 0,1^2 × 0,2
    = 4000 × 2 × 10^-3
    = 8