Bantuin kerjain dong + caranya tq before

[tex] \frac{x + 5}{2x - 4} \leqslant 0 \\ x + 5 = 0 \\ x = - 5 \\ \\ 2x - 4 = 0 \\ 2x = 4 \\ x = \frac{4}{2} \\ x = 2 \\ \\ \sqrt{3x - 2} > 4 \\ ( \sqrt{3x - 2} {)}^{2} > ( {4}^{2} ) \\ 3x - 2 > 16 \\ 3x > 16 + 2 \\ 3x > 18 \\ x > \frac{18}{3} \\ x > 6[/tex]