³log (2x-5) = ⁴log (2x-5))

[tex] {}^{3} log(2x - 5) = {}^{4} log(2x - 5) \\dgn \: syarat \: x > \frac{5}{2} \\ \\ {}^{3} log(2x - 5) = \frac{ {}^{3} log(2x - 5) }{ {}^{3} log(4) } \\ {}^{3} log(4) {}^{3} log(2x - 5) = {}^{3} log(2x - 5) \\ {}^{3} log(2 {}^{2} ) {}^{3} log(2x - 5) = {}^{3} log(2x - 5) \\ 2. {}^{3} log(2 {}^{} ) {}^{3} log(2x - 5) - {}^{3} log(2x - 5) = 0 \\ {}^{3} log(2x - 5) \times (2. {}^{3} log(2) - 1) = 0 \\ \\ bagi \: kedua \: ruas \: dgn \: 2. {}^{3} log(2) - 1 \\ sehingga \\ {}^{3} log(2x - 5) = 0 \\ 2x - 5 = 1 \\ 2x = 1 + 5 \\ 2x = 6 \\ x = 3[/tex]

³log (2x − 5) = ⁴log (2x − 5)
³log (2x − 5) = ³log (2x − 5) / ³log 4
³log 4 . ³log (2x − 5) = ³log (2x − 5)
³log 2² . ³log (2x − 5) = ³log (2x − 5)
2. ³log 2 . ³log (2x − 5) = ³log (2x − 5)
2. ³log 2 . ³log (2x − 5) − ³log (2x − 5) = 0
³log (2x − 5) . (2. ³log 2 − 1) = 0
³log (2x − 5) = 0
2x − 5 = 1
2x = 1 + 5
2x = 6
x = 6/2
x = 3