jika f(x)=2pangkat x,tentukan:f(2x-5)/f(2x-3)

jawav


f(x) = 2ˣ

f(2x-5)= 2²ˣ⁻⁵
f(2x-3) = 2²ˣ⁻³

f(2x -5) / f (2x-3) =  (2)⁽²ˣ⁻⁵⁾⁻⁽²ˣ⁻³⁾ = (2)⁻²
f(2x-5)/ f(2x -3) = 2⁻² = 1/4