^2 log (x-2) + ^2 log (x-1) = 2

Kelas 10 Matematika
Bab Logaritma

²log (x - 2) + ²log (x - 1) = 2
²log ((x - 2)(x - 1)) = 2
(x - 2)(x - 1) = 2²
x² - 3x + 2 - 4 = 0
x² - 3x - 2 = 0
a = 1; b = -3; c = -2.

x12 = (-b +- √(b² - 4ac))/2a
x12 = (3 +- √((-3)² - 4 . 1 . (-2)))/(2 . 1)
x12 = (3 +- √(9 + 8))/2
x12 = (3 +- √17)/2
x1 = (3 + √17)/2
x2 = (3 - √17)/2

Syarat :
x - 2 > 0
x > 2

x - 1 > 0
x > 1

HP = { (3 + √17)/2 }