Persamaan garis berikut yang melalui titik (2,-3) dan sejajar garis 2x-3y+5=0 adalah

garis ax + by = c1 sejajar dengan garis ax + by = c2
dimana c1 ≠ c2

2x - 3y = -5 sejajar dengan garis 2x - 3y = c
garisnya melewati (2,-3) maka
2x - 3y = c
2(2) - 3(-3) = c
4 + 9 = c
c = 13

jadi per. garisnya adlah
2x - 3y = 13

[tex]2x - 3y + 5 = 0 \\ - 3y = - 2x - 5 \\ y = \frac{ - 2}{ - 3} x - \frac{ - 5}{ - 3} \\ y = \frac{2}{3} x - \frac{5}{3} \\ \\ m = \frac{2}{3} [/tex]
persamaan garis
[tex]y - y1 = m(x - x1) \\ y - ( - 3) = \frac{2}{3} (x - 2) \\ 3(y + 3 )=2x - 4 \\ 3y + 9 = 2x - 4 \\ 3y + 9 - 2x + 4 = 0 \\ \\ 3y + 13 - 2x = 0[/tex]